Question

find the value
cos45⁰/sec30⁰ ×1/sec60⁰​

Answer 1

Step-by-step explanation:

cos 45°/sec30°×1/sec60°

(1/√2)/(2)×1/2

1/2√2×1/2

1/4√2

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Answer 2

$\frac{\sqrt{6} + 2}{4}$

Step-by-step explanation:

Given,

\frac{cos 45°}{sec 30°} * \frac{1}{sec 60°}

= $\frac{\frac{1}{\sqrt{2} }}{\frac{2}{\sqrt{3} } }$ + $\frac{1}{2}$

= 1/$\sqrt{2}$ * $\sqrt{3}$/2 + 1/2

= $\sqrt{6}$/4 + 1/2

= $\frac{\sqrt{6} + 2}{4}$

Thus, the value of cos45⁰/sec30⁰ × 1/sec60⁰​ =  $\frac{\sqrt{6} + 2}{4}$

Learn more: Trignonometry

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