Math, asked by hemu1176, 9 months ago

Find the value for k for which x^4+10x^3+25x^2+15x+k exactly divisible by x+7

Answers

Answered by goyalsunil1967
10

Answer:

k=-91

Step-by-step explanation:

As factor is x+7

then

x+7=0

x=-7

then in palce of x we have to use -7

-7^4+10(-7)^3+25(-7)^2+15(-7)+k=0

2401-3430+1225-105+k=0

91+k=0

k=-91

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