Find the value for k for which x^4+10x^3+25x^2+15x+k exactly divisible by x+7
Answers
Answered by
10
Answer:
k=-91
Step-by-step explanation:
As factor is x+7
then
x+7=0
x=-7
then in palce of x we have to use -7
-7^4+10(-7)^3+25(-7)^2+15(-7)+k=0
2401-3430+1225-105+k=0
91+k=0
k=-91
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