Question

Find the value in the attachment.​

Answer 1

Answer is given in the pic.

Answer 2

Answer:

65/8

Step-by-step explanation:

$a + \frac{1}{a + 2} = 0 \\ \frac{a(a + 2)}{a + 2} = 0 \\ a(a + 2) = 0$

Hence, a=0 or a=-2

But putting a=-2 in original equation will give:

$- 2 + \frac{1}{ - 2 + 2} = - 2 + \frac{1}{0} = undefined$

Therefore, a=0

${(a + 2)}^{3} + \frac{1}{{(a + 2)}^{3} } = ? \\ = {(0 + 2)}^{3} + \frac{1}{{(0+ 2)}^{3} } = 8 + \frac{1}{8} = \frac{65}{8} = 8\frac{1}{8}$