find the value iota^9+iota^10
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Answer:
i^9+i^10
= i^ 1+i^2
= where i^1=i and i^2 = (-1)
= so, (i-1) is the value of the que.
(In order to compute i^n for n>4, we divide n by 4 and the remainder becoms the power like in i^9 we divided it by 4 and got the remainder 1)
Hope you got that...!
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