Question

.Find the value of 0.23(bar on 23) +0.32 (bar on 2)

Answer 1

Given :   0.23(bar on 23) +0.32 (bar on 2)   $0.\overline{23}$   +   $0.3\overline{2}$  

To find : Value

Solution:

0.23(bar on 23) +0.32 (bar on 2)

$0.\overline{23}$   +   $0.3\overline{2}$

A = $0.\overline{23}$    

100A  =  $23.\overline{23}$    

100A - A = $23.\overline{23}$   - $0.\overline{23}$    

=> 99A  = 23

=> A = 23/99

B  = $0.3\overline{2}$

10B  = $3.\overline{2}$

100B = $32.\overline{2}$

=> 90B = 29

=> B = 29/90

A + B

= 23/99  + 29/90

= (230 + 319)/990

= 549/990

= 183/330

= 61/110

= $0.55\overline{45}$

$0.\overline{23}$   +   $0.3\overline{2}$   =  $0.55\overline{45}$       = 61/110

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Answer 2

Step-by-step explanation:

Given .Find the value of 0.23(bar on 23) +0.32 (bar on 2)

• Given 0.23 bar + 0.32 bar on 2
• We need to find the value for the given problem.
• Let m = 0.2323
• Multiply by 100 we get
• 100 m = 23.2323
• Subtracting both the equations we get
• 99 m = 23
• So m = 23 / 99
• Now let n = 0.3222
• Multiply by 10 we get
• 10 n = 3.222
• Multiply by 100 we get
• 100 n = 32.22
• Subtracting both the equations we get
• 90 n = 29
• Or n = 29 / 90
• Adding both m and n we get
• So m + n = 23 / 99 + 29 / 90
•                = 230 + 319 / 990
•              = 549 / 990
•               = 183 / 330  
•             = 61 / 110

Reference link will be

https://brainly.in/question/2018253