Question

x^2+2xy=16 , 3x^2-6=4xy-2y^2

Answer 1

Answer:

Step-by-step explanation:

2X²+2Y²-6XY=-10(AFTER ELIMINATING)  2x²+2y²-6xy+10=0(by using general formula) x=1.5 and y=1.5

Answer 2

Given : x²+2xy=16 ,   3x²-6=4xy-2y²  

To find : Integral Solution

Solution:

x²+2xy=16 ,

3x²-6=4xy-2y²

x²+2xy=16 ,

=> 2xy=16 - x²

3x²-6=4xy-2y²

=>3x²- 6 = 2(2xy) - 2y²

=>3x²- 6 = 2(16 - x²) - 2y²

=> 3x²- 6 = 32 - 2x²  - 2y²

=> 5x² + 2y²   =  38

Lets check integral Values

x = 1   =>  y²  = 33/2  

x = 2  =>  y² = 9  => y = ± 3    

x = 3 or more not Possible

as x² is there hence  

Possible solutions

x = 2  , y = 3

x = - 2  &  y = - 3

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