Question

Find the value of 0 if equation
Cos o x² - 2 sin ex-coso = 0 has
real roots​

Answer 1

Step-by-step explanation:

Apply the Formula =( a+ b) (a-b)

= a^2-b^2

Here, ((3x+2y)(3x-2y) (9x^2+4y^2))

=(9x^2-4y^2)(9x^2+4y^2g

again apply the same formula..........

Answer is..... 81x^4-16y^4