Question

Find the value of 0 in each of the following if :
(i) 2 cos 30 = 1
(ii) 2√3 tan = 6
(iii)1-tan square theta /1+tan square theta =1/2

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Answer 1

1. 2Cos30° = 1

From L.H.S

2×1/2 = 1 ( Cos30 = 1/2)

Hence L.H.S = R.H.S. prooved

2. 2√3 tan 60° = 6

From L.H.S

2√3 ×√3 = 6 (tan60° = √3)

Hence L.H.S = R.H.S

3. (1-tan^2 theta)/(1+ tan^2theta) = 1/2