Math, asked by psoniya043, 4 months ago

find the value of 1 ^0 × 2^0+3^0×4^0+5^0×6^0​

Answers

Answered by kukusaini74510
1

Answer:

 {a}^{0}  = 1 \\ so \: that \: 1 \times 1 + 1 \times 1 + 1 \times 1 \\  = 1 + 1 + 1 \\  = 3

Answered by nishtha123cba
1

Answer:

3

Step-by-step explanation:

= 1 ^0 × 2^0+3^0×4^0+5^0×6^0​

=1 × 1 + 1 × 1 +1 × 1

=1+1+1

=3

hope it helps mark as brainliest !!!

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