Math, asked by clkima403, 1 month ago

find the value of (1/1√2)+(1/√2+√3)+(1/√3+2)

Answers

Answered by minatibose51

0

Answer:

The value of 1/1+√2 + 1/√2+√3 + 1/√3+√4 +1/√4+√5 + 1/√5+√6 + 1/√6+√7+1/√7+√8+1/√8+√9 is 1

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