Find the value of : (1+2^0)^2×2^2
Answers
Answered by
0
Answer:
As we know that,
n
0
=1
n
−1
=
n
1
Therefore,
(3
0
+4
−1
)×2
2
=(1+
4
1
)×4
=(
4
4+1
)×4
=
4
5
×4
=5
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Answered by
1
Answer:
16
Step-by-step explanation:
(1+2^0)^2×2^2
=(1+1)^2×2^2
=2^2×2^2
=2^(2+2) [a^m×a^n=a^(m+n)]
=2^4
=16
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