Math, asked by ravikanttunwal1227, 1 year ago

Find the value of
1^3+3^3+5^3+7^3+9^3+11^3+..............+29^3=? With formula?

Answers

Answered by clockkeeper
4

we can write above question as

( {1}^{3}  +  {2}^{3}  + .... +  {29}^{3} ) - ( {2}^{3}  +  {4}^{3}  + .... {28}^{3} ) \\  = ( {1}^{3}  + ....+  {29}^{3} ) -  {2}^{3} ( {1}^{3}  + .... +  {14}^{3} ) \\  =  { (\frac{29.(29+ 1)}{2} )}^{2}  - 8 {( \frac{14.(14 + 1)}{2} )}^{2}  \\  = 189225 - 88200 \\  = 101025


ravikanttunwal1227: thanks dear
Answered by t52140612
0

Answer:

we can write above question as

(1³ +2³+ +29³)- (2³ +4³ +....28³)

(1³+ +29³) - 2³ (1³ + +14³)

189225-88200

=101025

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