find the value of (1-i)^2 complex numbers
Answers
Answered by
6
Answer:
-2i
Step-by-step explanation:
(1-i)^2 = 1 ^2+ i^2 - 2i
since i^2 = -1
therfore , ans is -2i
hope it helps!!
Answered by
3
Given: ( 1 - i)²
To Find : Value
Solution:
( 1 - i)²
use identity
(a - b)² = a² + b² - 2ab
a = 1 , b = i
= 1² + i² - 2(1)(i)
= 1 + i² - 2i
i² = - 1
= 1 + (-1) - 2i
= 0 - 2i
= -2i
( 1 - i)² = -2i
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