*Find the value of (1 - i)⁴
Answers
Answer:
Decompose your complex vector z=(1+i) in two subvectors:
z=1+i=1+i
The first (black) term is the positive unit real vector (this is always 1). Use this black handle for scaling and rotation.
The residual z−1=i (in your case is purely real). In the figure this is the red line.
Now our starting point is (1+i)1 .
To obtain (1+i)2 grab the black handle, scale it to the length of your previous endpoint |1+i|=(√2) and rotate it to that endpoint, with tan−1(11)=45 degrees. Scale the complete triangle, and now the endpoint of the scaled red vector, is the new complex value, being (1+i)2 .
To obtain (1+i)3 , grab the black handle of the initial triangle again, and scale it to have a length of |(1+i)2|=2 , and rotate it now with 90 degrees. Scale the complete triangle, and now the endpoint of the red vector is at (1+i)3 .
...etcetera...
Second example
Let's repeat this for taking the second power of z=2+2i .
First decompose z into the positive unit real vector (1) and the residual:
2+2i=1+(1+2i)
And use the black handle for scaling and rotation:
Answer:
hope this answer is helpful for you my friend..