find the value of
1- sin^2 theta/1+cos theta
Answers
Answered by
1
Answer:
Here,
1
−
(
sin
2
θ
1
−
cos
θ
)
=
−
cos
θ
L
H
S
=
1
−
(
sin
2
θ
1
−
cos
θ
×
1
+
cos
θ
1
+
cos
θ
)
=
1
−
sin
2
θ
(
1
+
cos
θ
)
1
−
cos
2
θ
...
.
.
→
(
1
−
cos
2
θ
=
sin
2
θ
)
=
1
−
(
sin
2
θ
)
(
1
+
cos
θ
)
sin
2
θ
=
1
−
(
1
+
cos
θ
)
=
1
−
1
−
cos
θ
=
−
cos
θ
=
R
H
S
Step-by-step explanation:
Answered by
0
Hope it helps you...... .....
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