Math, asked by abdul8467, 1 year ago

find the value of (1-sin^A)sec^A​

Answers

Answered by yajmera8
2

(1-sin^2A)sec^2A

=(1-sin^2A)1/cos^2A

=1/cos^2A - sin^2A/cos^2A

=sec^2A - tan^2A

we know that, 1 + tan^2A= sec^2A

=sec^2A-tan^2A = 1

So , answer is equal to 1

Answered by Kripa1311
4
I Hope it helps you please mark it as brilliant answer
Attachments:
Similar questions