find the value of
1. tan 49'/cot 41'
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Step-by-step explanation:
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Answered by
0
Answer:
The value of
cot41
o
tan49
o
=
cot41
o
tan(90
o
−41
o
)
=
cot41
o
cot41
o
=1
[∵tan(90
o
−θ)=cotθ]
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