Three resistors of 62, 32 and 22 are connected together so that the resistance is greater than 612 but less than 8.2. Draw a diagram to show this arrangement and calculate its total resistance.
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This is one example. I hope this is helpful for you.
We connect the resistance of 3Ω and 2Ω in parallel to each other and then connect this (parallel combination) to the 6Ω resistance in series. The required arrangement is as shown in figure. The equivalent resistance of 3Ω and 2Ω in parallel.
1/R = 1/3 + 1/2 = 2 + 3/6 = 5/6
Or R = 6/5Ω = 1.2Ω.
Thus, the total resistance of the set up is (1.2 + 6)Ω = 7.2Ω
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