find the value of 1 upon root 5 + root 2
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1/√5+√2 × √5-√2/√5-√2
=√5-√2/(√5)^2-(√2) [(a+b)(a-b)=a^2+b^2]
=√5-√2/5-2
=√5-√2/3
=√5-√2/(√5)^2-(√2) [(a+b)(a-b)=a^2+b^2]
=√5-√2/5-2
=√5-√2/3
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