Question

find the value of (1-w-w²)³*(1-w+w²)³ where w is the one of the complex cube root of unity

Answer 1

Dear here is ur solution,

=(1-w-w²) ³(1-w+w²) ³

On solving first [1-(w+w²)] ³
We know that 1+w+w²=0
So w+w²=-1
Putting its value
[1+1]³=8
On solving second (1-w+w²) ³
=[(1+w²) -w] ³
Putting value of 1+w²=-w
(-w-w) ³=-8w³
We know that w³=1 so -8w³=-8
Hence (-8)×8
=-64

Hope it will help you

Answer 2

Answer:

$(1 -w + w 2 )3$