Question

Find the value of (-10-10)÷{-10-(-10-10)}

Answer 1

Answer:

done

Step-by-step explanation:

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Answer 2

Answer:

The correct answer is $(-10-10) \div\{-10-(-10-10)\}=-2$.

Step-by-step explanation:

PEMDAS rule says that the order of operation begins with the parentheses first or the calculation which exists enclosed in brackets. Then the operation exists completed on exponents(degree or square roots) and later we do functions on multiplication and division and at last addition and subtraction.

P – Parentheses First

E – Exponents

M – Multiplication

D – Division

A – Addition

S – Subtraction

Given:

$(-10-10) \div\{-10-(-10-10)\}$

To find:

The value of $(-10-10) \div\{-10-(-10-10)\}$

Step 1

Let $(-10-10) \div\{-10-(-10-10)\}$

Follow the PEMDAS order of operations

Calculate within parentheses $(-10-10): \quad-20$

$=-20 \div\{-10-(-10-10)\}$

Step 2

Calculate within parentheses $\{-10-(-10-10)\}: \quad 10$

$=-20 \div 10$

Multiply and divide (left to right) $-20 \div 10:-2$

=-2

Therefore, the value of $(-10-10) \div\{-10-(-10-10)\}$ is -2.

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