Question

find the value of 100 joule on a system which has 20 centimetre 250 gram and the half minute as fundamental unit of length mass and time​

Answer 1

Answer:

Explanation:

Here n 1 = 100 J

M1 = 1 kg

L1 = 1m

T1 = 1 sec

And M2 = 250g

L2 = 20 g

T2 = 30 sec

[ M1 ] ^ 1 [ L1 ] ^ 2 [ T1 ] ^-2 . n2= n1 --------------------------------------

[ M2 ] ^1 [ L2 ]^2 [ T2 ]^-2

Putting value in this formula we get

n2 = 100 [ 1000 / 250 ] x [ 100 / 20 ]^2 x

[ 1 / 30 ] ^ -2

n2 = 100 x 4 x 25 x 900

n2 = 9 x 10^6 new units

Answer 2

Explanation:

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