Physics, asked by vini785, 1 year ago

The magnification formed by a concave lens of focal length of 20 cm and object is at 15 cm

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Answers

Answered by karurobo
0

the answer is minus four by seven....

-4/7

Answered by abhishek2708
0

F=5 cm

V=-2 cm (virtual image)

Lens formula= 1/u - 1/v = 1/f

1/-20 - 1/u= 1/5

1/u= - 1/20 - 1/5= -5/20

U=-4 cm

Manification, m= v/u= -20/-4 = +5

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