Question

Find the value of 101×101 using suitable
identities

Answer 1

101x101=$101^{2}$

=$(100+1)^{2}$

Using $(a+b)^{2}$

=  $a^{2}$+  $b^{2}$  +2ab

=  $101^{2}$ + $1^{2}$ +2×100×1

=10000+1+200

=10000+201

=10201.

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