Question

*If p, q, r are the zeroes of a cubic polynomial ax3 + bx2 + cx + d, then p + q + r =….....​

Answer 1

Step-by-step explanation:

p+q+r= -(coeff of x²)/coeff of x³

p+q+r= -b/a

Answer 2

Answer:

−c/d

Step-by-step explanation:

Given that

p(x)=ax^3+bx^2+cx+d .........(1)  where a=0 is a cubic polynomial  

And p,q,r are the zeroes of the polynomial p(x)

We all know that

p+q+r= -a/b= Sum of the roots

pq+qr+rp= c/a = Product of roots taken two at a time

pqr=−d/a

​ = product of roots

In the Question

1/p + 1/q + 1/r

= pq + qr + rp/pqr

=c/ a/−d/a

−c/d

​

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