Question

Find the value of 103suquare using identity.​

Answer 1

The identity is (a+b)²=a²+2ab+b²

Let, a=100 and b=3

So,

(100+3)²

= (100)²+2×100×3+(3)²

= 10000+600+9

= 10609

So, the answer is 10609

Answer 2

answer-

(103)²

--identity using identity (a + b)²=a²+2ab+b²

a=100

b=3

(100+3)²=100²+2*100*3 +3²

(103)²=10000+600+9

(103)²=10609