find the value of 104^2 - 103^2
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If there is a more simpler way please inform me
104^2-103^2
=(100+4)^2-(100+3)^2
we know,(a+b)^2=a^2+b^2+2*a*b
apply it here and we get
100^2+800+16-(100^2+600+9)
=100^2+800+16-100^2-600-9
cancel the 2 100^ 2 since its sign is opposite (100^2-100^2=0)
also, 800-600=200
and 16-9=7
therefore, 104^2-103^2=200+7=207
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