Question

find the value of 10C4​

Answer 1

Answer:

yes the answer is 201

Step-by-step explanation:

10 choose 4 = 201 possible combinations.201 is the total number of all possible combinations for choosing 4 elements at a time from to distinct elements without considering the order of elements in statistics & probability survey or experiment.

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Answer 2

Answer:

210

Step-by-step explanation:

This question is of "Combinations", which is

"The number of selection of "n" different things taken "r" at a time"

which is represented as

$^{n}C_{r} = \frac{n!}{(n - r)! \times r!}$

where "!" represents factorial which is used as such,

n! = n × (n-1) × . . . × 1

So, for the required question,

$^{10}C_{4} = \frac{10!}{(10 - 4)! \times 4!}$

=$^{10}C_{4} = \frac{10!}{(6)! \times 4!}$

=

$^{10}C_{4} = \frac{10 \times 9 \times 8 \times 7 \times 6!}{6! \times 4!}$

=

$^{10}C_{4} = \frac{10 \times 9 \times 8 \times 7}{4!}$

=

$^{10}C_{4} = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1}$

=

$^{10}C_{4} = \frac{10 \times 9 \times 8 \times 7}{8 \times 3}$

=

$^{10}C_{4} = \frac{10 \times 3 \times 7}{1}$

=

$^{10}C_{4} = 210$

Hence, the required value is 210.