Question

find the value of (-12)³+7³+5³ using special identity​

Answer 1

Answer:

1260

Step-by-step explanation:

Here, a= -12 ; b=7 ; c=5. a+b+c=-12+7+5. =0.

We know that if a+b+c=0 , then a³+b³+c³=3abc.

Then, (-12)³+7³+5³ =3(-12)(7)(5)

= -1260.