Find the value of 12th term from the last term of following A.P. 56,63,70,.........329.
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Step-by-step explanation:
This is an A.P
a=56
d= 63-56
=7
tn= 329
tn=a+(n-1)d
329= 56+(n-1)×7
329-56=(n-1)×7
273=(n-1)×7
273/7=n-7
39+7=n
n= 32
Therefore the last term is 32nd term
therefore the 12th term from last is 20th term
t12=56+(12-1)×7
= 56+11×7
=56+77
= 133
t12=133
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