Question

find the value of (2^0+3^0+4^0)-(4^0-3^0-2^0)​

Answer 1

Step-by-step explanation:

those values whose power is zero the answer of that value is always 1. Now

(2^0+3^0+4^0)-(4^0-3^0-2^0)

(1+1+1)-(1-1-1)

(3)-(-2)

3+2

5