Question

find the value of (2-¹+4-¹)÷ (2)-²

Answer 1

your answer is 3
hope so it will help u

Answer 2

$(2^{-1} +4^{-1})$ ÷ $(2)^{-2}=3$

Step-by-step explanation:

We have,

$(2^{-1} +4^{-1})$ ÷ $(2)^{-2}$

To find, the value of $(2^{-1} +4^{-1})$ ÷ $(2)^{-2}=?$

∴ $(2^{-1} +4^{-1})$ ÷ $(2)^{-2}$

$=(\dfrac{1}{2^1}+\dfrac{1}{4^1})$ ÷ $\dfrac{1}{2^2}$

Using identity,

$a^{-m}=\dfrac{1}{a^m}$

$=(\dfrac{1}{2}+\dfrac{1}{4})$÷ $\dfrac{1}{4}$

$=\dfrac{2+1}{4}\times \dfrac{4}{1}$

$=\dfrac{3}{4}\times \dfrac{4}{1}$

= 3 × 1

= 3

Hence, $(2^{-1} +4^{-1})$ ÷ $(2)^{-2}=3$