Question

Find the value of 2^1+x if 3^x+1=9^x-2

Answer 1

3^x+1 = 9^x-2
= 3^2(x-2)
Now bases are same so we can equate their powers.
x+1 = 2(x-2)
x+1 = 2x-4
x=5
2^1+x = 2^1+5 = 2^6 = 64