Question

find the value of 2^2+log3 base 2​

Answer 1

Answer:

.12 is the answer:-

Step-by-step explanation:

2^(2 + log 3 to the base 2)

So OK let’s start.

2^(2+log 3 to the base 2)

we can write it as

2^(log4 to the base 2 + log 3 to the base2)——————-{log 4 to the base 2 = 2}

=2^(log(4 *3) to the base 2)

=2^(log 12 to the base 2)

=12^(log 2 to the base 2)

=12^1

if you have confusion then see the attachment also:-

=12....Ans

Answer 2

Answer:

$2 {}^{2 + log_{2}(3) }$

$= 2 {}^{2} \times 2 {}^{ log_{2}(3) } \: \: \: \: \: \: \: \: (a {}^{m + n} = {a}^{m} {a}^{n} )\\ = 4 \times 3 = 12$

Hope it's helpful