Question

find the value of: 2(cos^2 45° + tan^2 60°) -6(sin^2 45° -tan^2 30°)​

Answer 1

tan(60°) = √3

Cos(45°) = 1/√2 = Sin(45°)

tan(30°) = 1/√3

Zzust put these values in question.

2[ (1/√2)² + (√3)² ] - 6[ (1/√2)² - (1/√3)² ]

→ 2[ 1/2 + 3 ] - 6[ 1/2 - 1/3]

→ 2(7/2) - 6(1/6)

→ 7 - 1

→ 6 _____________( Ans.) ✓✓

Hope it helps.

^_°