Find the value of 2^n+2^n-1/2^n+1-2^n
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(2^n+2^n-1)/(2^n+1-2^n)
=(2^n+2^n*1/2)/(2^n*2-2^n)
=[2^n(1+1/2)]/[2^n(2-1)]
after cancellation
=(3/2)
=(2^n+2^n*1/2)/(2^n*2-2^n)
=[2^n(1+1/2)]/[2^n(2-1)]
after cancellation
=(3/2)
Shabeena:
No
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