Question

find the value of 2 tan 30 / 1 + tan ^2 30 + 1 - tan^2 45 / 1 + tan^2 45​

Answer 1

Answer:

Identity used

$sin2x = \frac{2tanx}{1 + {tan}^{2} x} \\ cos2x = \frac{1 - {tan}^{2} x}{1 + {tan}^{2} x}$

Step-by-step explanation:

$2 tan 30 / (1 + tan ^2 30) + (1 - tan^2 45) /( 1 + tan^2 45) \\ </h3><h3>= sin 60° + cos 90° \\ \frac{ \sqrt{3} }{2} + 0 \\ = \frac{ \sqrt{3} }{2}$

Answer 2

Answer:

$\frac{ \sqrt{3} }{2}$

is the answer....