Math, asked by pathakpakhi55, 11 months ago

find the value of √(21+4√5+8√3+4√15)​

Answers

Answered by pal69
1

Answer:

√(21+4√5+8√3+4√15)

√(21+2√20+2√48+2√60)

√(12+5+4+2√5*4+2√4*12+2√5*12)

√((√12) ²+(√5) ²+(√4) ²+2√5*12+2√5*4+2√4*12)

using identity,

a²+b²+c²+2ab+2bc+2ca=(a+b+c) ²

so,

√((√12) ²+(√5) ²+(√4) ²+2√5*12+2√5*4+2√4*12) =

(√12+√5+√4) =2√3+√5+2.

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Answered by gchahat675
4

Answer:

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