find the value of √(21+4√5+8√3+4√15)
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Answer:
√(21+4√5+8√3+4√15)
√(21+2√20+2√48+2√60)
√(12+5+4+2√5*4+2√4*12+2√5*12)
√((√12) ²+(√5) ²+(√4) ²+2√5*12+2√5*4+2√4*12)
using identity,
a²+b²+c²+2ab+2bc+2ca=(a+b+c) ²
so,
√((√12) ²+(√5) ²+(√4) ²+2√5*12+2√5*4+2√4*12) =
(√12+√5+√4) =2√3+√5+2.
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