Math, asked by cheralabaijukum1, 1 year ago

find the value of [23^2 + 2^2 )^2/3 + (140-19)^1/2 ]^2

Answers

Answered by faizysuri
1
   [(23^2+2^2)^2/3 +(140-19)^1/2]^2
= [(529+4)^2/3  + (121)^1/2]^2
= [(533)^2/3 + 11]^ 2
= [ 65.738 + 11]^2
= 5888.755

this is as per ques . But surely there is something missing or wrong in ques .
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