Math, asked by akash385, 1 year ago

solve(x-7)(x-9)=48 when x>0.

Answers

Answered by dhruvsh
0
X^2 -9x-7x + 63 = 48
x^2 - 16x + 15 = 0
X^2 - 15x - x + 15 = 0
x ( x -15) -1 (x - 15)=0
X-1 = 0 or x-15 = 0
Thus x = 1 or x = 15.
Answered by bishtdikshantdp2x1gj
0
(x - 7) (x - 9) = 48

x² - 9x - 7x + 63 = 48
x² -16x +15 = 0
x² -15x -x +15 =0
x(x-15) -1(x-15) =
(x - 1) ( x - 15 = 

x = 1 , 15
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