Question

find the value of (256/625)^ -1/2​

Answer 1

BRAINLIEST PLZZZZZ......

Answer 2

$(\dfrac{256}{625})^{\dfrac{-1}{2}}$

Rewrite the fraction. Use $\dfrac{-a}{b} = \dfrac{a}{-b} = -\dfrac{a}{b}$

☛ $(\dfrac{256}{625})^{-\dfrac{1}{2}}$

Express with a positive exponent. Use $(\dfrac{a}{b})^-n = (\dfrac{b}{a})^n$

☛ $(\dfrac{625}{256})^{\dfrac{1}{2}}$

Transform the equation. Use $a^\dfrac{m}{n} = \sqrt[n]{a^m}$

☛ $\sqrt{\dfrac{625}{256}}$

Calculate the roots

☛ $\boxed{\boxed{\dfrac{25}{16} \: or \: 1.5625}}$