Math, asked by sweety13280, 6 months ago

Find the value of 27a³+b³,if 3a+b=12 and ab=5​

Answers

Answered by vipashyana1
2

Answer:

27a³+b³=1188

Step-by-step explanation:

3a+b=12

Cubing on both the sides

(3a+b)³=(12)³

(3a)³+(b)³+3(3a)(b)(3a+b)=(12)³

27a³+b³+(9ab)(3a+b)=1728

27a³+b³+9(5)(12)=1728

27a³+b³+540=1728

27a³+b³=1728-540

27a³+b³=1188

Therefore, the value of 27a³+b³ is 1188.

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