Find the value of 27a³+b³,if 3a+b=12 and ab=5
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Answer:
27a³+b³=1188
Step-by-step explanation:
3a+b=12
Cubing on both the sides
(3a+b)³=(12)³
(3a)³+(b)³+3(3a)(b)(3a+b)=(12)³
27a³+b³+(9ab)(3a+b)=1728
27a³+b³+9(5)(12)=1728
27a³+b³+540=1728
27a³+b³=1728-540
27a³+b³=1188
Therefore, the value of 27a³+b³ is 1188.
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