find the value of 27x^3+8y^3 if 3x+2y=20 and xy=11/9
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Answer:
Step-by-step explanation:
We know that
a^3 + b^3 = (a + b)^3 + 3ab(a + b)
Now, We set our question to this formula,
(3x)^3 + (2y)^3 = (3x + 2y)^3 + 3*3x*2y(3x + 2y)
(3x)^3 + (2y)^3 = (20)^3 + 18(11/9)(20)
(3x)^3 + (2y)^3 = 8000 + 440
(3x)^3 + (2y)^3 = 8440
Hence, (3x)^3 + (2y)^3 is 8440.
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