Math, asked by deathclicker, 4 months ago

find the value of 2a^2+b^2+1 if a=0 , b= 1 ? ​

Answers

Answered by sishaan540
0

Answer:

Value of 2a^{2} +b^{2} + 1 = 2

Step-by-step explanation:

if a=0 , b=1

replacing the values -:

2(0)^{2} + 1^{2} + 1

-: 0+1+1

= 2

Therefore the value of 2a^{2} +b^{2} + 1 = 2

Hope this was the answer you were looking for ..

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