Math, asked by anuvindpandey, 1 year ago

find the value of 2a-b+c,when a=1,b=-2,c=-1


music87: =2a-b+c=2(1)-(-2)+(-1)=2+2-1 l=4-1=3

Answers

Answered by pavamuruganpbcfes
15
Here your answer friend
2a-b+c
So, 2(1)-(-2)+(-1)
2+2-1
4-1
3
Hope this helps you friend
Thanks

anuvindpandey: thanku friend
Singhjagseer: welcome
Answered by jaya8765
0

Answer:

The value of 2a-b+c,when a=1,b=-2,c=-1 is 3

Step-by-step explanation:

2a-b+c

given that a=1,b=-2,c=-1

substitute the given values in the above equation

=2(1)-(-2)+(-1)

after substituting the given values the given equation is:

=2+2-1

=4-1

=3

Quadratic equations  are the polynomial conditions of degree 2 of every one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general type of a quadratic condition where 'a' is known as the main coefficient and 'c' is known as the outright term of f (x). The upsides of x fulfilling the quadratic condition are the foundations of the quadratic condition (α, β).

The quadratic condition will continuously have two roots. The idea of roots might be either genuine or nonexistent.

A quadratic polynomial, when likened to nothing, turns into a quadratic condition. The upsides of x fulfilling the condition are known as the foundations of the quadratic condition.

General from: ax2 + bx + c = 0

Models: 3x2 + x + 5 = 0, - x2 + 7x + 5 = 0, x2 + x = 0.

for more examples visit the links given blelow:

https://brainly.in/question/9210451

https://brainly.in/question/3088869

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