Find the value of 2sin15degre cos75degre
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Hey friend✋! here is your answer
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◆ To find - {2sin15° Cos75°}
✔️Formula => 2sinA cosB= sin(A+B)+sin(A-B)
✅By comparison - A=15° & B=75°
✔️2sin15° cos75°=
✅sin(15+75)+sin(15-75)
✔️Sin(90)+sin(-60)
✅1+(-√3/2). { sin90°= 1 & sin60°=√3/2}
✔️1-√3/2
✅Take LCm
✔️2-√3/2
So,
value of 2sin15° Cos75° is 2-√3/2
_________________________
⭐️Hope it helps you⭐️
#Rohan ( Maths aryabhatta)♥️
____________________________
◆ To find - {2sin15° Cos75°}
✔️Formula => 2sinA cosB= sin(A+B)+sin(A-B)
✅By comparison - A=15° & B=75°
✔️2sin15° cos75°=
✅sin(15+75)+sin(15-75)
✔️Sin(90)+sin(-60)
✅1+(-√3/2). { sin90°= 1 & sin60°=√3/2}
✔️1-√3/2
✅Take LCm
✔️2-√3/2
So,
value of 2sin15° Cos75° is 2-√3/2
_________________________
⭐️Hope it helps you⭐️
#Rohan ( Maths aryabhatta)♥️
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