Math, asked by mahareddynikita, 1 year ago

find the value of (2x^2+1)^2.​

Answers

Answered by Tiger887
2

Answer:

To Find :-

 {( {2x}^{2}  + 1)}^{2}

Solution

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 { {2x}^{2} }^{2}  +  {1}^{2}  + 2 \times  {2x}^{2}  \times 1 \\  =  {4x}^{4}  +  {4x}^{2}  + 1

▪️◾◼️Hope this helps◼️◾▪️

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