Question

Find the value of 2x^3 + 6x

Answer 1

Answer :-

(C) 3

Step-by-step explanation :-

$\displaystyle{\sf{x=2^{1/3}-2^{-1/3} }}$   (Given)

We need to find the value of 2x³ + 6x.

To find the value, we can directly substitute the given value of x.

$\displaystyle{\rm{ 2x^3+6x=2(2^{1/3}-2^{-1/3})^3+6(2^{1/3}-2^{-1/3})}}\\\\\displaystyle{\rm{\longrightarrow 2x^3+6x= 2[(2^{1/3\times3}-2^{-1/3\times3})+6(2^{1/3}-2^{-1/3})]}}\\\\\displaystyle{\rm{\longrightarrow 2x^3+6x= 2[2-2^{-1}-3(2^{1/3}-2^{-1/3})+6 6(2^{1/3}-2^{-1/3}) ]}}\\\\\displaystyle{\rm{\longrightarrow 2x^3+6x= 4-1-6(2^{1/3}-2^{-1/3})+6(2^{1/3}-2^{-1/3} )}}\\\\\displaystyle{\rm{\longrightarrow 2x^3+6x= 3}}$

► Hence, the final answer is 3.

Answer 2

Step-by-step explanation:

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Answer♡

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your answer is option C

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