Question

3.14 in c++ must be declared as?

Answer 1

Answer:

C++11 allowed lambda functions to deduce the return type based on the type of the expression given to the return statement. C++14 provides this ability to all functions. It also extends these facilities to lambda functions, allowing return type deduction for functions that are not of theFor example, to declare a variable of type int called x and initialize it to a value of zero from the same moment it is declared, we can write: int x = 0; A second method, known as constructor initialization (introduced by the C++ language), encloses the initial value between parentheses ( () ): form return expression; .

Explanation:

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