find the value of 2x²+ 5x² +7x² -x +41,when x =-2 -root 3 i
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Answer:
The answer is 214.564
Step-by-step explanation:
Given 2x²+5x²+7x²-x+41
if x= -2√3
substitute 'x'value in the equation
2(-2√3)²+5(-2√3)²+7(-2√3)²-(-2√3)+41
2(4x3)+5(4x3)+7(4x3)+2√3+41
2x12+5x12+7x12+2√+41
26+60+84+2√3+41
the value of √3=1.732
211+2x1.732
211+3.564
214.564
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