Question

find the value of 2x²+ 5x² +7x² -x +41,when x =-2 -root 3 i​

Answer 1

Answer:

The answer is 214.564

Step-by-step explanation:

Given 2x²+5x²+7x²-x+41

if x= -2√3

substitute 'x'value in the equation

2(-2√3)²+5(-2√3)²+7(-2√3)²-(-2√3)+41

2(4x3)+5(4x3)+7(4x3)+2√3+41

2x12+5x12+7x12+2√+41

26+60+84+2√3+41

the value of √3=1.732

211+2x1.732

211+3.564

214.564